Monday, August 2, 2010

Experment 4

This experiment was done using a breadboard, muliti meter, a 12v adjustable power supply 1x resistor 1k.ohm, 1x 5v1 zener diode, and 1x diode 1N4007.


Once I had completed building my circuit i did a range of tests at 10v and 15v 

At 10v the voltage drops are as recorded ..
Vd across zener diode 4.68v
Vd across diode .65v
Vd across both zener diode and diode 5.34v
Vd across resistor 4.87v

10v 4.87 / 1000
=0.00487a

the calculated current for this circuit at this voltage is 0.00487a using ohms law.

At 15v the voltage drops are as recorded..
Vd across zener diode 4.83v
Vd across diode .68v
Vd across both zener diode and diode 5.52v
Vd across resistor 9.11v
15v  9.11 / 1000
=0.00911a

          the calculated current for this circuit at this voltage is 0.00911a using ohms law.                
  
What is happening here is that because the value of both the zener diode and diode is 5v the calculated Vd is similar at both voltage settings.









                                           

1 comment:

  1. above ohms law picture refrenced ......fenway@boston.k12.ma.us ....

    ReplyDelete